**Time speed and Distance**is also a favourable math chapter for all competitive exams. Always, ask one or more question from this chapter in the exam. Already, we have learned Profit and Loss, boat and stream formula,

**Time and works**, Easy Division rules,

**Simple and compound interest**chapters, Average, and many more

**shortcuts math formulas**. Now, we are going to learn

**shortcuts formula for time speed and distance**chapter. As per the regular post, fast of all, I'm giving you some basic formula in an image. You may download this image for regular views to memorize this shortcuts formula easily.

Above, just I had given you some basic shortcuts formula of

**Time Speed and Distance**chapter. But sometimes, we need to convert time and distance unit according to the asked question. Because in question, you may see variations in hours, minute and second and on another hand Km and metre. So, we need it to convert as per the requirement of questions. Km/hour will be converted in meter/hour multiplying by 18/5 and meter/hour will be converted in km/hour multiplying by 5/18.

Here, I'm solving some basic questions using above formulas which will help you to observe how to execute the

**time speed and distance problems**easily? Please note, usually, this type of question is not asking for competitive exams. Yet, these formulas are very important to solve advance level

**time speed and distance problems**because these are basic and

**heart and soul**formula of this chapter.

**Solved question from the Time-speed and Distance**

A bus travelled 200 km in 4 hours. In what speeds ran the bus?

__Solution:__

Directly apply the formula Speed= Distance/time

⇒Speed = 400/4 Km/h

⇒50 Km/hour.

**Problems 2:**

A bus is running at the speed of 60 km per hour. How many kilometres will cover in 5 hours?

__Solution:__

Apply the formula

Traveled distance= Speed*Time

So the distance will cover =5 x 60 km = 300 km.

Now we are moving to Advance shortcut formulas of Time and speed math chapter. Which is usually asks on competitive examination like SSC, PSC, Railway recruitment, I.B and many more examinations.

Suppose, a train reached its destination at speed of X km/hour and come back the station at the speed of Y km/hour, then the average speed of the train was

In above formula, X and Y are the speed value of the train. It may be in meters, Km or mile unit. Please remember both journeys should be the same distance. otherwise, this formula does not apply.

Read also,

**Shortcut formula for time speed and distance**

Suppose, a train reached its destination at speed of X km/hour and come back the station at the speed of Y km/hour, then the average speed of the train was

In above formula, X and Y are the speed value of the train. It may be in meters, Km or mile unit. Please remember both journeys should be the same distance. otherwise, this formula does not apply.

**Example question from Time-Speed and distance chapter:**

A train started running to a station at the speed of 60 km per hour and came back at the speed of 50 km per hours, then what is the speed of the train, in its whole journey?

**Solution:**Simply apply the previous formula. Here two different speeds are 60Km/h and 50 Km/h. Here we may be thought 60 as X and 50 is Y. So here we can find out the average speed of the train was

(2XY)/X+Y.

⇒2*60*50/(60+50)

⇒6000/110

⇒54.5454 Km/ hour.

Shortcuts Formula Time and Speed 2:

When a person or object cover a certain distance of his whole journey at the speed of X km per hours and rest journey covers in Y km per hours. If the man complete his whole journey in T hours then the distance between two ending places will be-

Shortcuts Formula Time and Speed 2:

When a person or object cover a certain distance of his whole journey at the speed of X km per hours and rest journey covers in Y km per hours. If the man complete his whole journey in T hours then the distance between two ending places will be-

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