Problem on trains problems and math tricks #3 ~ Math Tricks

Shortcuts quantitative aptitude formula competitive exams

Thursday, 24 August 2017

Problem on trains problems and math tricks #3

This is the third tutorial of Problem on train aptitude sequences. However, this chapter related to the shortcut math chapter Time speed and distance. Though, we have divided it into separate math sections. Because all the examiners are asking the question from Time-speed and distance aptitude with the problems on trains topic. Some primary term can be applied in this chapter. So, this point of view we are discussing in this page related to problems on trains to earn quicker math solution formulas and observe aptitude question quickly.

Aptitude question condition & shortcuts formula

A train started the journey from one station to another station at the speed of X Km/hour. Another train which is started the trip from the same position and same direction at the rate of Y Km/Hour. The second train started travel T hour later from the first train. When will be both trains in the same place from the first train journey? Here must be the speed of first train greater than the second train.
Aptitude shortcuts formula:- The method for this kind of question will be

Please note: Here X & Y is the speeds of two train, where X is first the train and Y is other trains. T is the time difference between two trains starting the journey.
Problem on train Quantitative aptitude 1:-
A train started a journey from the station Howrah to Gauhati at the speed of 60 Km/h. After Two hours another train began its drive at the speed of 80 km per hour. When will the second train catch first train from its started time?
Quick math solution by math tricks:- 
Here is the first train running at the speed of 60 km per hour and second train 80 km per hour. The second train started two hours late. The time needs to second train to catch the first train
 Aptitude question Condition2:
A train A km distance covers at the speed of X km/h, and also it covers B km distance at the rate of Y km/h. The average speed of the train will be:-
Shortcut formula:-
(A+B) / { (A/X)/ (B/Y)}

Question:- A passenger train covers 200 km at the speed of 50 km/h. Another passenger train covers 150 Km at the speed of 30 km per hour. What is the average speed of both trains?
Quicker math solution by Maths Tricks:-
Here two distances are 200 and 150km.The speed of two trains 50 and 30 km per hour. Now we will use the formula by putting value.
 (200+150)/{(200/50)+(50+30)} =350/{600+750/150} =350/{(1350/150)}=350*150/1350 =350/9 =38 8/9 km/ hour

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