The

**boats and streams**chapter is depending on Time-speed and distance section, if you have learned the**time speed and distance**chapter before, then you can adopt this particular math chapter quickly. So, here we are discussing the**boats and streams shortcut formula**mainly. Before moving to our main shortcut**aptitude formulas**, I want to inform you that the boats are run on the water. And water should have a stream, so boat runs along the streams or the opposite of the flow. This is the primary factor to pay attention while we are solving the**aptitude problems**on the chapter**Boats and Streams.**The boats are flows two types. When the boat runs along the streams is called**downstream and upstream**is call while the boat swims against the streams. Note that the boats flow on the still water.
Already, you have learnt the formula for

**Time speed and Distance**while the moving object was moving on roads or railways. Now you will learn the same method, but the moving thing will swim on the steam or in still water. Hope you guess easily which kind of questions will have asked from this chapter. Here are some last line examples question from the boats and streams section.
What was the speed of the boat in still water?

What was the speed of the steam?

What is the speed rate in Upstream, down steams or in still water?

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The original speed of a boat in still water is A km/hour. When the rate of the stream is B km/hour. If the boat flows on that stream, then find the speed of the boat in downstream and upstream.

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Speed of the boat in upstream will:-

(Speed in still water – rate of stream) = (50-10) Km/hour = 40 km/hour

Speed in Downstream will:-

(Speed in Still water + Rate of Stream)

=50+10 Km/hour = 60 Km/ hour

The speed of a boat U km/hour in upstream and D Km/hours in downstream. What will be the speed in still water? What is the rate of the Streams?

Just apply above formula for the speed of the boat in still water (U+D)/2.

**Boat and Stream aptitude, shortcut formulas and Quicker Solution.**

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**Shortcut Formula 1:**

The original speed of a boat in still water is A km/hour. When the rate of the stream is B km/hour. If the boat flows on that stream, then find the speed of the boat in downstream and upstream.

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**Aptitude Question 1****:**

**Aptitude Question 1**

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A boat runs at the rate of 50 km per hour in downstream. If the rate of steam is 10 km per hour, then find the Speed of the boat in still water?

Quicker solution:

(Speed in still water – rate of stream) = (50-10) Km/hour = 40 km/hour

Speed in Downstream will:-

(Speed in Still water + Rate of Stream)

=50+10 Km/hour = 60 Km/ hour

__Shortcuts formula 2__

The speed of a boat U km/hour in upstream and D Km/hours in downstream. What will be the speed in still water? What is the rate of the Streams?

Boats and streams formula |

__:- The upstream of a boat is 40 Km per hour, and the Downstream is 60 Km per hour, Then find the speed of the boat in still water.__

**Example Aptitude**1)

**Quicker Solution**:Just apply above formula for the speed of the boat in still water (U+D)/2.

**Example Aptitude**2:
The rate of a boat in upstream 60 km per hour and 80 km in Downstream. Then find the speed of the Steam?

In the last aptitude solution, we used shortcut formula to find the rate of the boat in still water. Now we are going find the speed of the streams. Here we will use the formula (D-U)/2. Because in question declare the rate of the boat in up and downstream. And we have to find the current rate.let's look at below.

In the last aptitude solution, we used shortcut formula to find the rate of the boat in still water. Now we are going find the speed of the streams. Here we will use the formula (D-U)/2. Because in question declare the rate of the boat in up and downstream. And we have to find the current rate.let's look at below.

Boat and streams aptitude solution.2 |

Look at quicker math solution:

The formula is

Here A is the upstream and B is downstream. The answer will come by putting the value of A and B in the Quicker math solution formula. Let's look at the solution

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